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blondinia [14]
3 years ago
13

sharon is planning a cookout for 42 people. each guest will get 1 veggie burger. sharona will put one slice of cheese on half of

the burgers. cheese slices come in packs of 8. write and solve an equation to find the number of packs of cheese, p, that sharon needs to buy.
Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

3

Step-by-step explanation:

42 divided by 2 equals 21

21 divided by 8 equals 2.625

therefore, sharon must buy 3 packets of cheese.

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Question 20 read the question and type your response in the box below the question. your response will be saved automatically. w
grandymaker [24]
You're looking for something like y=2x+3 and 2y=4x+6?
3 0
3 years ago
I need help with 25 i dont know how to put it on a double line bar
Kipish [7]
Use proportion 
25%/100 division sign 10/x
100 * 10=25x
1000=25x
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x=40
so 40 is your answer
you welcome 
7 0
3 years ago
The diameter of the base of a cone measures 8 units. The height of the cone is 6 units. What is the volume of the cone in terms
Mekhanik [1.2K]

Answer:

V = 32 pi

Step-by-step explanation:

The volume of a cone is

V = 1/3 pi r^2 h

The radius is d/2 = 8/2 = 4

V = 1/3 pi (4)^2 * 6

V = 32 pi

5 0
3 years ago
In a drama classroom, 75% of the students are chosen to perform a play. Of those choosen, 15% have singing roles. What is the pr
Nikolay [14]

Answer:

1/5 or 0.2

Step-by-step explanation:

  1. probability=No of students with singing roles/No of people in the play
  2. 15/75=1/5 or 0.2
4 0
4 years ago
The theater director offered every member of the drama one vote for which play they preferred to perform. The director found tha
worty [1.4K]

Answer:

0.92 is the required probability.

Step-by-step explanation:

We are given the following in the question:

Percentage who voted for The Oddems Family = 35%

P(A) = 0.35

Percentage who voted for The Thirteenth Night = 57%

P(B) = 0.57

Percentage who did not vote = 8%

P(A^C\cap B^C) = 0.08

We have to find the probability that the group voted for "Oddems Family" or "Thirteenth Night".

Thus, we have to evaluate

P(A\cup B)

This can be done in the following manner:

P(A^C\cap B^C) = 0.08\\P(A\cup B)^C = 0.08\\P(A\cup B) = 1-0.08\\P(A\cup B) = 0.92

Thus, 0.92 is the probability  that the group voted for "Oddems Family" or "Thirteenth Night".

3 0
3 years ago
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