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Harlamova29_29 [7]
2 years ago
6

Factor completely. 7x²+28r-35 =

Mathematics
1 answer:
Marysya12 [62]2 years ago
8 0

7x^2 +28x -35 \\\\=7(x^2 +4x - 5)\\\\=7(x^2 +5x -x -5)\\\\=7\left[ x(x+5) -(x+5) \right]\\\\=7(x-1)(x+5)

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What is 321 rounded to the nearest 10
shtirl [24]
It would be 330 if rounded to the nearest 10th place
6 0
3 years ago
Can you explain to me (detailed) on how to do this problem? I will give you a brainly if you get this right.
7nadin3 [17]

Answer:

60 m^2

Step-by-step explanation:

To solve the area, solve the triangle and rectangle separately.

Solve the rectangle:

Multiply 10 and 4 to get the area of 40 m^2.

Solve the triangle:

Multiply 10 and 4, then divide by 2. The formula for a triangle's area is base*height/2. The area is 20.

Add together:

40+20 = 60 m^2

6 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
A parallelogram has a base of length 2x + 1 and a height of x + 3 and has an area of
storchak [24]

Answer:

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Step-by-step explanation:

Using the given expressions, we can write the area as ...

  A = BH

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In order for the parallelogram to have positive dimensions, the value of x must be 3. So, the base and height are ...

  base = 2(3) +1 = 7

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7 0
3 years ago
Read 2 more answers
Solve x − y = 5 for y.
AnnyKZ [126]

Answer:

-y=5-x

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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