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Mila [183]
3 years ago
11

The angle of elevation from a ball on a football field to the top of a 30-foot y'all goal post is 16 degrees 42'. How far is the

football from the base of the goal post? Round to the nearest tenth of a foot.
Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

  100.0 feet

Step-by-step explanation:

For an acute angle in a right triangle, the cotangent function is the ratio of the adjacent side to the opposite side:

  cot(16°42') = (distance to goal)/(30 ft)

Multiplying by the denominator, we have ...

  (distance to goal) = (30 ft)cot(16°42') = (30 ft)(3.33317) ≈ 100.0 ft

The football is 100.0 feet from the base of the goal.

_____

cot(16°42') = tan(73.3°)

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lozanna [386]

Answer:

x = 1/4

Step-by-step explanation:

First u swap the sides of the equation

8x = 2

then you divide both sides by 8 which gets you 1/4 or 0.025

6 0
3 years ago
Hugo plays basketball.
djyliett [7]

Answer:

170

Step-by-step explanation:

multiply 12×15=170

4 0
3 years ago
3. Find mZS.<br> Q= 5x + 2)<br> P= 10x - 3)<br> (7x - 11)=ºR<br> (13x - 31)º=S<br> (8x - 19)=T
azamat

Answer:

∠S = 151

Step-by-step explanation:

The figure shown is a pentagon

The angles in a pentagon add up to equal 540

Thus, ∠Q + ∠P + ∠T + ∠S + ∠R = 540

Or 10x - 3 + 5x + 2 + 7x - 11  + 13x - 31 + 8x - 19 = 540

This is the equation we will use to solve for x

Step 1 combine like terms

10x = 5x + 7x + 13x + 8x = 43x

-3 + 2 - 11 - 31 - 19 = -62

We now have 540 = 43x - 62

Step 2 add 62 to each side

-62 + 62 cancels out

540 + 62 = 602

we now have 602 = 43x

Step 3 divide each side by 43

43x / 43 = x

602 / 43 = 14

we're left with x = 14

Finally we plug in 14 for x in the given expression for ∠S

∠S = 13x - 31

* substitute 14 for x *

∠S = 13 ( 14 ) - 31

∠S = 13 * 14 = 182

182 - 21 = 151

Thus, ∠S = 151

5 0
3 years ago
The following piecewise function gives the tax owed, T(x), by a single taxpayer on a taxable income of x dollars.

T(x) = (i) De
Luda [366]

(i) To show that a piecewise function is continuous at a point, we need to show that the left hand and right hand limit "agree" with each other. In other words, we want:

\lim_{x\to 6061^-} T(x) = \lim_{x \to 6061^+} T(x)

Now, since we're given the constraints and the equation of each constraint, we notice that 6061^+ is a number that is slightly bigger than 6061. So we use the second equation. Do you see why?

In much the same way, 6061^- is a number that is slightly smaller than 6061. So we use the first equation. Again, do you see why? (Hint: look at the conditions on x for each equation).

So finally, computing each limit means just "plugging" 6061 into their respective equations. That is:

\lim_{x \to 6061^-} T(x) = 0.10\times 6061 = 606.1

\lim_{x \to 6061^+} T(x) = 606.1 + 0.18(6061 - 6061) = 606.1

Since your limits match, we say that, at the point x = 6061, T(x) IS continuous.

(ii) Repeat the process above with x = 32473.

(iii) Find a point of discontinuity just means your right hand and left hand limits do not match -- I'm not an economist, so I may not be of much help with the latter part of the question!

6 0
3 years ago
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Scientists often write very large or very small numbers using exponents. How might a scientist write the number shown using expo
Ludmilka [50]
Which number? I don’t see a number
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