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Mila [183]
3 years ago
11

The angle of elevation from a ball on a football field to the top of a 30-foot y'all goal post is 16 degrees 42'. How far is the

football from the base of the goal post? Round to the nearest tenth of a foot.
Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

  100.0 feet

Step-by-step explanation:

For an acute angle in a right triangle, the cotangent function is the ratio of the adjacent side to the opposite side:

  cot(16°42') = (distance to goal)/(30 ft)

Multiplying by the denominator, we have ...

  (distance to goal) = (30 ft)cot(16°42') = (30 ft)(3.33317) ≈ 100.0 ft

The football is 100.0 feet from the base of the goal.

_____

cot(16°42') = tan(73.3°)

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3 years ago
Find the MEAN for the data set: 6, 2, 7, 3,2
shtirl [24]

Answer:

4

Step-by-step explanation:

To find MEAN, add up <em>all</em> the values in a data set and then divide by the <em>number</em> of values.

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2 years ago
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What is the minimum value of the function g(x) = x2 - 6x – 12?<br> -21<br> 3-21<br> 3<br> 3+21
balandron [24]

Answer:

- 21

Step-by-step explanation:

The minimum value occurs at the vertex of the function

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Given

f(x) = x² - 6x - 12

add/ subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 - 12

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4 0
3 years ago
What is the slope of the line represented by the equation 4x+3y=12
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3 0
3 years ago
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sashaice [31]

Answer:

8 minutes.

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Let m represent number of minutes.

We have been given that Mike is biking to catch up with his sister who is already 1200 yards ahead of him. His sister is biking at a speed of 450 yards per minute.

So total distance covered by Mike's sister after m minutes would be 450m+1200.

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Now, we will equate both expressions to find minutes at which both distances will be equal as:

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Therefore, it will take after 8 minutes for Mike to catch his sister.

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