Answer:
0.9 for the top box and 1.68 for the bottom box
Step-by-step explanation:
give me brainliest answered on khan academy
Multiply 3 and 8 then you will have your answer
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
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</span>
Answer:
M. (4x-1) (x+4)
K. (3x-1)(2x-1)
L.(2x-7)(x+5)
N.3x^2-4x+39
O.(3x-1)(3x+4)
Sorry if it's wrong but that's what I got
Answer:
$43.20
Step-by-step explanation:
To find the original purchase price, write a proportion and solve. A proportion is an equation where two ratios are set equal.
If the discount if 15% then you pay 85%.
To solve for y, cross multiply the numerator and denominator of each fraction.
36.72(100) = 85y
3672= 85y
43.2 = y
