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dexar [7]
2 years ago
13

Doug mcdougal is whipping up 72 different snacks for his 12th annual blooper bowl bash he invited 138 guess but only 16 are comi

ng that doesn’t bother dog he still makes 100 bowls of nacho dip he makes twice as many bowls of chili how many guests are coming to the party
Mathematics
1 answer:
Anna71 [15]2 years ago
6 0

The number of guests coming to Doug McDougal party can be calculated to be 23 people.

<h3>What number of people are coming?</h3>

Doug invited 138 guests and out of this, only 1/6 will be coming.

The number of people coming is therefore:

= Number invited x Proportion coming

Solving gives:

= 138 x 1/6

= 23 people

Find out more on problems involving proportions at brainly.com/question/14581282.

#SPJ1

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HELPPPPPPPPPPP
kolbaska11 [484]

Answer:

V = 18.84 units³

Step-by-step explanation:

The formula for the volume of a cone of base radius r and height h is

V = (1/3)(pi)(r²)(h).

Here, with pi = 3.14, r = 3 and h = 2, we get:

V = 18.84 units³

5 0
3 years ago
What is the perimeter =26
UNO [17]
It depends upon the shape.  But perimeter in general is the sum of the outside measure.  Here, for whatever the shape is, the perimeter is 26
6 0
3 years ago
X^2 + Y^2 +ax + 2y + 3 = 0<br><br> What number is this equation the equation of a circle?
Sav [38]

Answer:

Eq: (x+a/2)²+(y+1)²=(a²-8)/4

Center: O(-a/2, -1)

Radius: r=0.5×sqrt(a²-8)

Mandatory: a>2×sqrt(2)

Step-by-step explanation:

The circle with center in O(xo,yo) and radius r has the equation:

(x-xo)²+(y-yo)²=r²

We have:

x²+y²+ax+2y+3=0

But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4

And

y²+2y+3=y²+2y+1+2=(y+1)²+2

Replacing, we get:

(x+a/2)²-a²/4+(y+1)²+2=0

(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4

By visual inspection we note that:

- center of circle: O(-a/2, -1)

- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)

6 0
3 years ago
7700÷623 with answer and remainder
Free_Kalibri [48]
7700/623
= 623*12 + 224

Therefore, the answer is 12 and the remainder is 224.

Hope this helps !

Photon
3 0
3 years ago
Read 2 more answers
I need help bad! I need help with the last question!
MAVERICK [17]
Use the fact that 1 axe head = 3.20 trade value.
Let N denote number of axe heads needed to trade for a trade gun.
3.20×N=120.00
》 N=120/3.2 which will give number of axe heads needed. Round to the nearest ones place if you must.
5 0
3 years ago
Read 2 more answers
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