The cost of 1 apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents
<em><u>Solution:</u></em>
Let "a" be the cost of 1 apple
Let "b" be the cost of 1 banana
Let "r" be the cost of 1 orange
<em><u>Given that Apple costs the same as 2 oranges</u></em>
cost of 1 apple = 2 (cost of 1 orange)
a = 2r -------- eqn 1
<em><u>Together, an orange and a banana cost 10 cents more than an apple</u></em>
cost of 1 orange + cost of 1 banana = 10 + cost of 1 apple
r + b = 10 + a --------- eqn 2
<em><u>Two oranges cost 15 cents more that a banana</u></em>
cost of 2 orange = 15 + cost of 1 banana
2r = 15 + b ----- eqn 3
<em><u>Let us solve eqn 1, eqn 2 and eqn 3</u></em>
From eqn 1 and eqn 3, substitute eqn 1 in eqn 3
a = b + 15 --- eqn 4
<em><u>Substitute eqn 4 in eqn 2</u></em>
r + b = 10 + b + 15
r = 10 + 15
<h3>r = 25</h3>
<em><u>Substitute r = 25 in eqn 3</u></em>
2(25) = 15 + b
50 - 15 = b
<h3>b = 35</h3>
<em><u>Substitute b = 35 in eqn 4</u></em>
a = 35 + 15
<h3>a = 50</h3>
Thus cost of one apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents