Answer:
a. a[1] = 3; a[n] = 2a[n-1]
b. a[n] = 3·2^(n-1)
c. a[15] = 49,152
Step-by-step explanation:
Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.
The first term is 3, and the common ratio is 2.
<h3>(a)</h3>
The recursive rule is ...
a[1] = 3
a[n] = 2×a[n-1]
__
<h3>(b)</h3>
The explicit rule is ...
a[n] = a[1]×r^(n-1)
a[n] = 3×2^(n-1)
__
<h3>(c)</h3>
The 15th term is ...
a[15] = 3×2^(15-1) = 3×2^14
a[15] = 49,152
Answer:
1/15
Step-by-step explanation:
2/5-1/3=6/15-5/15=1/15
Answer:
Slope = 0
So, the line is parallel to x-axis
Step-by-step explanation:
(x₁ , y₁) = (-8, -8) & (x₂ ,y₂) = (6 , -8)
![Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\=\frac{-8-[-8]}{6-[-8]}\\\\=\frac{-8+8}{6+8}\\\\= 0](https://tex.z-dn.net/?f=Slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%5C%5C%5C%5C%5C%3D%5Cfrac%7B-8-%5B-8%5D%7D%7B6-%5B-8%5D%7D%5C%5C%5C%5C%3D%5Cfrac%7B-8%2B8%7D%7B6%2B8%7D%5C%5C%5C%5C%3D%200)
Answer:
the number of recruits neither be college graduate and nor army veterans is 30
Step-by-step explanation:
The computation of the number of recruits neither be college graduate and nor army veterans is as follows;
= Total recruits - (college students + army veterans - both college graduates & army veterans)
= 120 recruits - (80 + 25 - 15)
= 120 recruits - 90
= 30
hence, the number of recruits neither be college graduate and nor army veterans is 30