Which what ? Put the question and will help you
Answer:
Step-by-step explanation:
Answer:

Step-by-step explanation:
we know that
<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.
To calculate combinations, we will use the formula

where
n represents the total number of items
r represents the number of items being chosen at a time.
In this problem

substitute

simplify



Answer:
0
Step-by-step explanation:
You can't make 0.2 as a whole number so we can round it to the nearest whole number, 0.
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.