HELPP ILL PUT YOU THE BRAINIEST The set of all values that a function can take as inputs is called the

According to a study by the American Pet Food Dealers association, 63 percent of U.S. households own pets. A report is being pre

Nastasia [14]

Answer

$z=\frac{0.7 -0.63}{\sqrt{\frac{0.63(1-0.63)}{300}}}=2.511$

$p_v =2*P(z>2.511)=0.012$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of households with pets is different from 0.63. This data disagree deom the Pet food association

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

X=210 represent the households with pets

$\hat p=\frac{210}{300}=0.7$ estimated proportion of households with pets

$p_o=0.63$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is 0.63:

Null hypothesis: $p=0.63$

Alternative hypothesis: $p \neq 0.63$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.7 -0.63}{\sqrt{\frac{0.63(1-0.63)}{300}}}=2.511$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.511)=0.012$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of households with pets is different from 0.63. This data disagree deom the Pet food association

7 0

3 years ago

Three students compared their math scores: Lea correctly answered 35 out of 37 items, Jay scored 97% on the exam, and Roy answer

Artemon [7]

Roy has the highest score of 97.5% as a percent. Leas is 94%.

7 0

3 years ago

Sarabi drove 20 mi at 40 mph. How long did she drive?

liubo4ka [24]

1/2 of the time

d=st
distance=speed times time
we want to find time
divide both sides by speed
d/s=t

d=20
s=40
20/40=t
1/2=t
this is in hours

she drove for 1/2 hour or 30 mins

8 0

3 years ago

The mad scientist need one third of the eyeball how many eyeball is that

inna [77]

Answer:

.33 as a decimal or 33%

Step-by-step explanation:

Divide 1/3 and get .33 as your decimal. To convert to a percentage multiply your decimal by 100. (<em>.33 x 100 = 33 </em>)

4 0

3 years ago

Read 2 more answers

I am giving 50 points. I only need help with this last page! Please someone help me.