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AysviL [449]
3 years ago
8

PLEASE HELP DUE TODAY !

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0

Answer: Each bag of chips is $0.25, each soda is $0.75.  

(0.25 x 8) + (0.75 x 4) = 5

2 + 3 = 5

(0.25 x 4) + (0.75 x 8) = 7

1 + 6 = 7

igor_vitrenko [27]3 years ago
5 0

Answer:

let x be chips and y be sodas

8x + 4y = 5 ---> for the first hint

4x + 8y = 7------> second hint

0.25 cents is how much chips costs

and 0.75 cents is how much sodas costs

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The amount of time devoted to studying statistics each week by students who achieve a grade of A in the course is a normally dis
svlad2 [7]

Answer:

a) 11.7% of students study for more than 10 hours per week.    

b) 35.6% of student spends between 7 and 9 hours studying.

c) 1.6% of  students spend fewer than 3 hours studying.

d) 5% of all A students spend studying 4.0455 or less hours during a week.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.5 hours

Standard Deviation, σ = 2.1 hours

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(students study for more than 10 hours per week)

P(x > 10)

P( x > 10) = P( z > \displaystyle\frac{10 - 7.5}{2.1}) = P(z > 1.1904)

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Calculation the value from standard normal z table, we have,  

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b) P(student spends between 7 and 9 hours studying.)

P(7 \leq x \leq 9) = P(\displaystyle\frac{7 - 7.5}{2.1} \leq z \leq \displaystyle\frac{9-7.5}{2.1}) = P(-0.2380 \leq z \leq 0.7142)\\\\= P(z \leq 0.7142) - P(z < -0.2380)\\= 0.762 - 0.406 = 0.356 = 35.6\%

P(7 \leq x \leq 9) = 35.6\%

c)  P(students spend fewer than 3 hours studying)

P(x < 3) = P(z < \displaystyle\frac{3-7.5}{2.1}) = P(z < -2.1428)

Calculating the value from the standard normal table we have,

P( x < 3) =0.016 = 1.6\%

d)  P(X < x) = 0.05

We have to find the value of x such that the probability is 0.035

P( X < x) = P( z < \displaystyle\frac{x - 7.5}{2.1})=0.05  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 7.5}{2.1} = -1.645\\x = 4.0455  

5% of all A students spend studying 4.0455 or less hours during a week.

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