By setting up a system of equations we can easily solve this problem. Let's denote Jane's working hours with x and Jack's working hours with y. Since they don't want to work more than 65 hours, the first equation is x+y=65. The second equation is 14x+7y=770. By solving this system of equation
, we find that y=20 hours, which is Jack's maximum working hours.
Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5
Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
<span>$8.50/hr multiplied by 16 hours worked equals $136. $136 minus (7.65%)(136) equals $125.60. $125.60 minus (9.15%)(136) equals $113.16. Travel expenses of $6.00 multiplied by 4 equals $24. $113.16 minus 24 equals $89.16 net income.</span>
Ratio 1:2:3 means we have x, 2x and 3x as the three parts
x+2x+3x = 42
6x = 42
6x/6 = 42/6
x = 7
Since x = 7, this means 2x = 2*7 = 14 and 3x = 3*7 = 21
Dividing 42 into the ratio of 1:2:3 means we have 7:14:21 as the answer
If we divide all three parts of 7:14:21 by the GCF 7, we reduce it down to 1:2:3
As a check,
7+14+21 = 21+21 = 42
so it works out
The answer would be 1/4 or
i hope this answer helps!
