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shtirl [24]
2 years ago
8

What is the third quartile of the set of data shown below?

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
4 0
That would be D because you need to make sure the numbers aren’t closed or way behind
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21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with mea
Anika [276]

Answer:

About 3 years Speedy Jet printers be guaranteed.

Step-by-step explanation:

Given : Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with

mean \mu = 4 and standard deviation  \sigma = 0.78

If the company wishes to replace no more than 10% of the printers.

To find : How long should Speedy Jet printers be guaranteed ?

Solution :

Using Z- table,  

Z value corresponding to 10% or 0.10 = -1.28.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

The value of x is given by,

x=(z\times \sigma)+\mu

Substitute the values,

x=(-1.28\times 0.78)+4

x=-0.9984+4

x=3.0016

So, approx 3 years.

Therefore, About 3 years Speedy Jet printers be guaranteed.

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There are 40 apples in a crate.
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35 apples are still good
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2 years ago
Zared plays basketball on his high school team. One of the things he needs to practice is his free throws. On his first shot, th
Marat540 [252]

Answer:

lol brainliest

Step-by-step explanation:

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3 years ago
Veterinarians often use nonsteroidal anti-inflammatory drugs (NSAIDs) to treat lameness in horses. A group of veterinary researc
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Answer:

C. The chance to be selected into the sample was the same for all veterinarians

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