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3 years ago

Find the missing length of 26cm 10cm of the right triangle

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer:

24cm

Step-by-step explanation:

A^2 + B^2 = C^2 soo 10^ + B^ = 26^2 so 100 + B^2 = 676 subtract 100 from 676. Then take the square root of 576 and you’ll get 24. So B = 24cm

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galina1969 [7]

Answer:

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Step-by-step explanation:

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3 years ago

What value(s) of x will make each equation below true

Dahasolnce [82]

We need to solve for x. Let's try problem b:

$2x-6=3x+1-x-7$

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

$2x-6=2x-6$

Since this is true, your answer would be:

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Let's solve for problem c:

$3x+1=43$

Let's isolate x, so subtract 1 from both sides:

$3x=42$

Since x can't have a coefficient, divide both sides by 3:

$\frac{3x}{3}=\frac{42}{3}$

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Let's try problem d:

$4x-1=4x+7$

Let's get our whole numbers on the right side. Add 1 to both sides:

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Since this is not true, your answer would be:

No solution

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4 years ago

Which expression is equivalent to 2 to the power of 4 times 2 to the power of negative 7?

deff fn [24]

Answer:

$2^{-3}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$ , thus

$2^{4}$ × $2^{-7}$ = $2^{(4-7)}$ = $2^{-3}$

3 0

4 years ago

Help a girl out? im terrible with this

Archy [21]

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3 years ago

Read 2 more answers

The Environmental Protection Agency (EPA) has contracted with your company for equipment to monitor water quality for several la

max2010maxim [7]

Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A total of 15 devices will be used.

This means that $n = 15$

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that $p = 0.05$

What is the probability that one of the devices fail?

This is $P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

36.58% probability that one of the devices fail

7 0

3 years ago