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2 years ago

Please help me!

Mathematics

2 answers:

IrinaVladis [17]2 years ago

8 0

Radius is 13/2=6.5
Diameter is 13

s344n2d4d5 [400]2 years ago

6 0

Answer:

Radius = 6.5cm

Diameter = 13cm

Step-by-step explanation:

The diameter is the length of one side of a circle to the other. It's already given in the diagram as 13cm.

The radius is half of the diameter. 13 divided by 2 is 6.5cm.

You might be interested in

7x-3y=-7 slope of line perpendicular

kap26 [50]

Answer: -3/7

Step-by-step explanation:

The first step is to find the slope of the line

y = mx + c where m is the slope of the line
Rearrange the equation and we get

3y = 7x + 7
y = 7x/3 + 7/3

So the slope of the line 7x - 3y = -7 is 7/3

There is another rule that states: The product of the slopes of two lines perpendicular to each other is -1

So, the slope of the line perpendicular to 7x - 3y = -7 is -1/(7/3) = -3/7

3 0

2 years ago

A rocking horse has a weight limit of 60 pounds. What percentage of the weight limit is 33 pounds? *

Fynjy0 [20]

Answer:

p = 55 %

Step-by-step explanation:

What percentage of the weight limit is 33 pounds?

p * weight limit = 33

p * 60 = 33

divide each side by 60

p = 33/60

p =.55

this is in decimal form

multiply by 100

p = 55 percent

4 0

3 years ago

Dy/dx if y = Ln (2x3 + 3x).

NeTakaya

Answer:

$\frac{6x^2+3}{2x^3+3x}$

Step-by-step explanation:

You need to apply the chain rule here.

There are few other requirements:

You will need to know how to differentiate $\ln(u)$ .

You will need to know how to differentiate polynomials as well.

So here are some rules we will be applying:

Assume $u=u(x) \text{ and } v=v(x)$

$\frac{d}{dx}\ln(u)=\frac{1}{u} \cdot \frac{du}{dx}$

$\text{ power rule } \frac{d}{dx}x^n=nx^{n-1}$

$\text{ constant multiply rule } \frac{d}{dx}c\cdot u=c \cdot \frac{du}{dx}$

$\text{ sum/difference rule } \frac{d}{dx}(u \pm v)=\frac{du}{dx} \pm \frac{dv}{dx}$

Those appear to be really all we need.

Let's do it:

$\frac{d}{dx}\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot \frac{d}{dx}(2x^3+3x)$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (\frac{d}{dx}(2x^3)+\frac{d}{dx}(3x))$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot \frac{dx^3}{dx}+3 \cdot \frac{dx}{dx})$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot 3x^2+3(1))$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (6x^2+3)$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{6x^2+3}{2x^3+3x}$

I tried to be very clear of how I used the rules I mentioned but all you have to do for derivative of natural log is derivative of inside over the inside.

Your answer is $\frac{dy}{dx}=\frac{(2x^3+3x)'}{2x^3+3x}=\frac{6x^2+3}{2x^3+3x}$ .

3 0

3 years ago

7. Match each expression in the left column with an equivalent expression in the right

kolezko [41]

Answer: that’s the question

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Josh believes the Spanish club students at his school have an unfair advantage in being assigned to the Spanish class they reque

Svetach [21]

You can calculate the following probabilities:
1. Given that a sampled student is in the Spanish Club, what is the probability they got the Spanish class they requested?
2. Given that a sampled student is not in the Spanish Club, what is the probability they got the Spanish class they requested? If there is a significant difference between the two probabilities, it indicates there is a bias in the selection procedure.

Given that, a sampled student is in the Spanish Club, the probability they got the Spanish class they requested is given by 265/335. Given that, a sampled student is not in the Spanish Club, the probability they got the Spanish class they requested is given by 100/165.

If a student is at the Spanish club, the probability they got the Spanish class they requested is 265/335 = 0.79. If a student is not in the Spanish club, the probability they got the Spanish class they requested is 100/165 = 0.61.

Based on the calculation, all students do not have an equal chance of getting into the Spanish class that they requested.

7 0

3 years ago

Read 2 more answers