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2 years ago

Mr. Kelner buys a $300 suit that is marked down by 20%. How much does Mr. Kelner save?

Mathematics

2 answers:

Talja [164]2 years ago

6 0

Answer:

Mr. Kelner is going to save $60

Step-by-step explanation:

VLD [36.1K]2 years ago

6 0

Answer:

He will save 60$

Step-by-step explanation:

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3 years ago

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9e - 7 = 7e - 11 solve for e

prisoha [69]

Answer:

e = -2

Step-by-step explanation:

9e - 7 = 7e - 11

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2 years ago

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Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

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3 years ago

Laurie bought 4 yards of brown braid trim, 7 yards of black lace, and 13 yards of gold ribbon. She paid $2.40 for each yard of r

Elza [17]

Answer:

24 yards, $77.40

Step-by-step explanation:

1) brown braid : 4*2.40 = $16.80

black lace : 7*2.40 = $29.40

gold ribbon : 13*2.40 = $31.20

2) 4 + 7 + 13 = 24 yards <

3) 16.80 + 29.40 + 31.20 = $77.40 <

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2 years ago

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