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konstantin123 [22]
2 years ago
8

The table represents a logarithmic function f(x). Use the description and table to graph the function, and determine the domain

and range of f(x). Represent the domain and range with inequality notation, interval notation, or set-builder notation. Explain your reasoning

Mathematics
1 answer:
dusya [7]2 years ago
4 0

The domain of the function is x > 0 and the range of the function is -∞ < f(x) < ∞

<h3>How to determine the domain?</h3>

This is the set of input values on the table.

All input values (i.e. the x values) on the table are greater than 0 i.e. x > 0

Using the inequality notation, the domain of the table is x > 0

<h3>How to determine the range?</h3>

From the table, the logarithmic function outputs all zero, positive and negative numbers.

This means that the range is the set of all real numbers i.e. -∞ to ∞

Using the inequality notation, the range of the table is -∞ < f(x) < ∞

Read more about domain and range at:

brainly.com/question/11787743

#SPJ1

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I need help pls thank you and I'll send better pics
kakasveta [241]
\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}

Explanation:

\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}

\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}\text{output = input + 5}

5 0
1 year ago
Choose the words or phrases that best complete the sentences.
ASHA 777 [7]
1) Could
2) Could, <span>but don't have to be</span>
5 0
3 years ago
Read 2 more answers
What is (−3.2)⋅1.7 multipluied
Natalka [10]

Answer:

-5.44

Step-by-step explanation:

multiply add negative sign

6 0
3 years ago
Read 2 more answers
Elena went on a 6-mile walk. She completed the first half of the walk 1 mi/h faster than usual and the second half of the walk 2
xxTIMURxx [149]

Answer:

Her usual rate is 0.8333 miles per hour.

Step-by-step explanation:

The velocity formula is given by:

v = \frac{d}{t}

In which d is the distance and t is the time.

She completed the first half of the walk 1 mi/h faster than usual

Her usual rate is v. 1mph faster is v + 1.

The second half of the walk 2 mi/h slower than the first half.

The first half is v + 1.

2mph slower is v + 1 - 2 = v - 1. Then

Total rate:

7.2 hours, and 6 miles. So

One half is v+1 and the other is v - 1. This is why each is multiplied by 0.5.

0.5(v + 1) + 0.5(v - 1) = \frac{6}{7.2}

0.5v + 0.5 + 0.5v - 0.5 = 0.8333

v = 0.8333

Her usual rate is 0.8333 miles per hour.

8 0
3 years ago
How do you solve f(x) = 800(1.09)3x
natta225 [31]

Answer:

2616x

Step-by-step explanation:

8 0
3 years ago
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