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Yakvenalex [24]
3 years ago
10

What is the answer to this problem?

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
0.4 is 10 times as much as 0.04 and 0.1 is 10 times as much as 0.01 and 1/10 of 1
0.9 is 10 times as much as 0.09 and 1/10 of 9
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Solve (x – 3)2 = 49. Select the values of x.
PIT_PIT [208]

Answer:

<h3>x = 27.5</h3>

Step-by-step explanation:

(x - 3)2 = 49 \\  \frac{(x - 3)2}{2}  =  \frac{49}{2}  \\ x - 3 = 24.5 \\ x - 3 + 3 = 24.5 + 3 \\ x = 27.5 \\

6 0
2 years ago
Read 2 more answers
A sequence starts from -2. The term to term rule is 'square and subtract 3' find the first six numbers of the sequence
alexandr1967 [171]

Answer:

The first six numbers are -2,1,-2,1,-2,1

Step-by-step explanation:

First term is -2

The term to term rule is 'square and subtract 3'

Second term=(-2)^{2} -3=1

Third term=(1)^{2} -3=-2

Fourth term=(-2)^{2} -3=1

Fifth term=(1)^{2} -3=-2

Sixth term=(-2)^{2} -3=1

The first six numbers are -2,1,-2,1,-2,1

6 0
2 years ago
. -5, 10, 7, 10, 9, 0, 1, 9, -1, 5 Work out the mean.
bezimeni [28]

Answer:

6

Step-by-step explanation: because its online

4 0
3 years ago
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is
Otrada [13]

Answer:

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 29.5

Standard deviation r = 5.2

Number of samples n = 59

Confidence interval = 90%

z-value (at 90% confidence) = 1.645

Substituting the values we have;

29.5+/-1.645(5.2/√59)

29.5+/-1.645(0.676982337100)

29.5+/-1.113635944529

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

7 0
3 years ago
sketch a unit circle with angle instandard positionquestions:a. For what values of 0 is the sine increasing? Decreasing?b. For w
liq [111]

We can draw a unit circle as:

The sine is the vertical leg (or vertical projection) of the triangle formed by the angle.

The cosine will be the horizontal leg (or horizontal projection) of this same triangle.

The hypotenuse of this triangle will be the radius if the unit circle (r = 1).

a) The sine will be increasing from θ = 0° until it reaches its maximum at 90°.

Then it will be decreasing for angles between 90° and 270°.

Between 270° and 0° it will be increasing again.

b) The cosine has a maximum value for an angle of 0°.

It will decrease until 180°.

Then it will be increasing from angles between 180° and 360°.

c) We can see in the unit circle that the sine is 0 when the angle is one the horizontal axis, like when θ = 0° or θ = 180°.

The cosine will be equal to 0 when the angle is vertical: θ = 90° and θ = 270°.

Answer:

a) Increasing: (0°, 90°) and (270°, 360°)

Decreasing: (90°, 270°)

b) Increasing: (180°, 360°)

Decreasing: (0°,180°).

c) Sin(θ) = 0 for θ = 0° and θ = 180°

Cos(θ) = 0 for θ = 90° and θ = 270°

4 0
1 year ago
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