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3 years ago

Find the product.

Mathematics

2 answers:

tankabanditka [31]3 years ago

8 0

the answer would be c

vichka [17]3 years ago

7 0

-2x2 + 6x :) hope it helps

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Find the slope of the line on the graph. Write your answer as a fraction or a whole number, not mixed number or decimal.

Vesna [10]

Answer:

<em>The slope is:</em>

$m=-\frac{3}{2}$

Step-by-step explanation:

The slope m of a line is calculated using the following formula

$m=\frac{y_2-y_1}{x_2-x_1}$

Where the points $(x_1, y_1)$ and $(x_2, y_2)$ are two points belonging to the straight line

Notice in the graph that the line passes through the points

(0, 2) and (2, -1)

Then the slope is:

$m=\frac{-1-2}{2-0}$

$m=\frac{-3}{2}$

4 0

3 years ago

Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

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3 years ago

What is the correct answer to 42r - 18

kotykmax [81]

Answer:

I'm working during the same thing

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3 years ago

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mihalych1998 [28]

23 / 50 = 0.46

0.46 converted to a percent is 46%

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