Let's start with the smallest prime number 2
60/2 = 30
Divide that result over 2
30/2 = 15
We can't divide this by 2 because 15/2 = 7.5 isn't a whole number
Let's move onto 3
15/3 = 5
The result is a prime number, so we stop.
The values we divided as denominators were: {2, 2, 3}
We add the result 5 to the set to completely list all of the prime factors of 60
The prime factorization would be
<h3>60 = 2*2*3*5</h3>
which is the same as saying
<h3>60 = 2^2*3*5</h3>
Answer: 27.42 ft
Step-by-step explanation:
To find the perimeter first we must find the circumference of the circles.
You can easily find the diameter by subtracting and you get 6.
Using the circle circumference formula c=2piR you get 9.42.
9.42 is our circumference of one circle.
You don't need to divide this by 2 because you already have 2 halves of a circle.
Next add all the sides which is 18.
Add this to the circumference we calculated earlier which gives you 27.42 ft.
Answer:
She need to buy 8 packs of rolls and 15 packs of sausages! The LCM is 240 so you would need to find out how many packs or rolls and how many packs of sausages equal 240!
Step-by-step explanation:
You cut out the question-
Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to

where
b is the length side of the square
we have

substitute

step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to

The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute


Therefore, the area of 2 "not-shaded" regions is:

and the area of 4 "not-shaded" regions is:

step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume

substitute