Question

Write the first five terms of the geometric sequence whose first terns 6, and whose common ratio is 3.

Answer 1

The first five terms of the geometric sequence is 6, 18, 54, 162 and 486

Geometric progression is given by:

$nth\ term=ar^{n-1}$

where a is the first term, r is the common ratio

Given that first term is 6, and common ratio is 3, Hence a = 6, r = 3

$First\ term=6\\\\Second \ term=6(3)^{2-1}=18\\\\Third \ term=6(3)^{3-1}=54\\\\Fourth \ term=6(3)^{4-1}=162\\\\Fifth \ term=6(3)^{5-1}=486$

The first five terms of the geometric sequence is 6, 18, 54, 162 and 486

Find out more on geometric sequence at: brainly.com/question/24355584