1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
we are given
we can see that 3 is not present in the options on exponent
so, we will try to get rid of exponent 3
we can write it as
now, we know that
so, we can plug it
and we get
so, option-2......................................Answer
You probably have done something like this and are confused by the directions.
Step One
Write down the equation and the givens.
P = 425
x is what you are trying to isolate.
P = 25x - (10x + 250)
Step Two
Remove the brackets on the right.
P = 25x - 10x - 250 Notice all those minus signs. The one on the outside of the brackets gets distributed just as thought there was a (say) - 5
Step Three
Collect the like terms on the right.
P = 15x - 250
Step Four
This really doesn't require a separate step, but I should have done it at the beginning. Put in P = 425
425 = 15x - 250
Step 5
Add 250 to both sides.
425 + 250 = 15x
675 = 15x
Step Six
divide by 15
675 / 15 = x
45 = x
He has to sell 45 calculators.
79+16, 94+1, 95 +0
Hope this helped !
Answer:
4.99 , 5 , 5.05 , 5.15 , 5.5
i hope this helps you!
