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Firdavs [7]
2 years ago
10

What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.

Mathematics
1 answer:
grigory [225]2 years ago
7 0

Answer:

C) \theta\approx\{0.3218,1.249,3.463,4.3908\}

Step-by-step explanation:

5\sin2\theta=3;\: 0\leq\theta\leq 2\pi\\\\\sin2\theta=\frac{3}{5}\\ \\2\theta\approx\{0.6436,2.498,6.926,8.7816\}\\\\\theta\approx\{0.3218,1.249,3.463,4.3908\}

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