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Lera25 [3.4K]
3 years ago
12

2. What decimal equals seven hundred forty-six thousandths?

Mathematics
2 answers:
damaskus [11]3 years ago
5 0
The correct answer is A because when you move the decimal over you’ll get 746,000
morpeh [17]3 years ago
4 0

Answer:

A. 0.0746

Step-by-step explanation:

Because it is in the thousandths place

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What is the area of this parallelogram?​
amid [387]

Answer:

A = 88 m^2

Step-by-step explanation:

The area of this parallelogram is found by

A = b*h

The base is equal to 4+7  and the height is  8

A = 11 *8

A = 88 m^2

8 0
3 years ago
280 gigabytes means?
PtichkaEL [24]

250 gigabytes (250 GB) = 268,435,456,000 bytes
250 gigabytes (250 GB) = 256,000 megabytes (MB)
In computing, the phrase 250 GB (or 250 gigabytes) is most commonly used in reference to disk storage and also data transmission (transfer capacity) for Internet account usage.
3 0
3 years ago
A set of laptop prices are normally distributed with a mean of 750 dollars and a standard deviation of 60
s344n2d4d5 [400]

Answer:

0.6

Step-by-step explanation:

Given: Mean= $750

          Standard deviation= $60

First, lets find out z-score of the interval between $624 and $768.

z score= \frac{x-mean}{Standard deviation}

z score= \frac{624-750}{60}= \frac{-126}{60}

∴ z score for $624 is -2.1

Now, finding z score for $768

Z score= \frac{768-750}{60} = \frac{18}{60}

∴ z score for $768 is 0.3

As per the z score table, the value for -2.1 is 0.0179 and for 0.3 is 0.6179

Now, subtracting the value to get proportion

0.6179-0.0179= 0.6

∴ There are 0.6 proportion of laptops are in the range of $624 and $768

         

7 0
3 years ago
Iodine-131 is used medically to study the activity of the thyroid gland. Iodine – 131 has a half-life of about 8 days. This mean
Nataliya [291]

Answer:

0.002 mg of sample will be left after 40 days.

Step-by-step explanation:

Half life of the iodine-131 =t_{\frac{1}{2}}= 8 days

Initial amount of iodine-131 =N_o= 64 milligrams = 0.064 g

Amount of iodine-131 left after the time of  40 days = N

Decay constant =\lambda = ?

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=0.0866 day ^{-1}

\log[N]=\log[N_o]-\frac{\lambda \times t}{2.303}

\log[N]=\log[0.064 g]-\frac{0.0866 day^{-1}\times 40 days}{2.303}

N=Antilog [-2.6979 g]

N = 0.002004 g = 0.002 mg

0.002 mg of sample will be left after 40 days.

4 0
3 years ago
Please help! Brainliest answer! thank you!1
kobusy [5.1K]

Answer:

I think it's A

Step-by-step explanation:

because none of the others appear to be correct

5 0
3 years ago
Read 2 more answers
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