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2 years ago

ZnS (s) + AIP(s) → AI₂S₂(s) + Zn P₂(s)

Chemistry

1 answer:

Allisa [31]2 years ago

3 0

Answer:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Explanation:

I believe you are asking for this reaction to be balanced. However, after looking more closely, those are not the products that would be created from the reactants. Assuming this is a double-displacement reaction, and taking the most common charges of the ions into consideration, the actual products would be AI₂S₃(s) + Zn₃P₂(s). I apologize if I assumed incorrectly.

For an equation to be balanced, there needs to be the same amount of each element on both sides of the equation.

The unbalanced equation:

ZnS (s) + AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Reactants: 1 zinc, 1 sulfur, 1 aluminum, 1 phosphorus

Products: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

As you can see, there is an unequal amount of each element on the reactants and products side. To balance the equation, coefficients in front of the compound(s) will be necessary.

The balanced equation:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Reactants: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

Products: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

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