Answer:
The answer to your question is: Q = 1383.06 J
Explanation:
Data
mass = 0.740 g
Initial Temperature = 23.4°
Final Temperature = 26.9°
Cp = 534 J/°C
mass of water = 675 ml
Q = ?
Formula
Q = mCpΔT
Process
Q = (0.740)(534) (26.9 - 23.4)
Q = (0.740)(534) (3.5)
Q = 1383.06 J
Answer:
A
Explanation:
In the scientific name limus polyphemus which the species is the classification group for polyphemus
Answer:
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Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
