Ask question

Ask question

All categories

Pachacha [2.7K]

3 years ago

12

How many atoms are in the product of the following reaction?

1 answer:

Zanzabum3 years ago

6 0

Answer:

Total of 5 moles of products in the reaction.

Explanation:

1: Calculate the number of atoms

2: convert from more to number

3: Done

Hope this helps.

You might be interested in

What is the price coke difference between a strong and weak acid?

KATRIN_1 [288]

Explanation:

Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.

H2 CO3 (acid)↔H+ + HCO3- (base)

MAY IT HELPS U MATE ☃️☃️

5 0

3 years ago

How is fluorine purified so that it is stable? If this is the same as how it was first purified, then state that it is.

krek1111 [17]

Answer:

it is the same way it is purified in the state

4 0

3 years ago

Determine what elements are denoted by 1s22s22p63s23p64s23d104p65s1

Brilliant_brown [7]

Answer:

Rubidium

Explanation:

Rubidium has atomic number 37 and belong to group one alkali metals and has one valence electron at the outermost shell whiz is 5s1

8 0

3 years ago

The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq

Pavlova-9 [17]

Answer : The molarity of $I_3^-$ in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

$2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)$

First we have to calculate the moles of $Na_2S_2O_3$ .

$\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}$

$\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole$

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of $I_3^-$ .

From the balanced chemical reaction, we conclude that

As, 2 moles of $S_2O_2^{-3}$ react with 1 mole of $I_3^-$

So, 0.007696 moles of $S_2O_2^{-3}$ react with $\frac{0.007696}{2}=0.003848$ mole of $I_3^-$

The moles of $I_3^-$ = 0.003848 mole

Now we have to calculate the molarity of $I_3^-$ .

$\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}$

Now put all the given values in this formula, we get:

$\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M$

Therefore, the molarity of $I_3^-$ in the solution is, 0.128 M

8 0

3 years ago

Which of the following is a producer? O mouse cactus O snake O goose

ValentinkaMS [17]

Answer:

cactus

Explanation:

Its a plant so it makes it own food

6 0

4 years ago