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yarga [219]
3 years ago
10

1. write a sentence that describes how the food changes in the stomach.

Chemistry
1 answer:
Advocard [28]3 years ago
8 0

Explanation:

This energy comes from the food we eat. Our bodies digest the food we eat by mixing it with fluids (acids and enzymes) in the stomach. When the stomach digests food, the carbohydrate (sugars and starches) in the food breaks down into another type of sugar, called glucose.

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For which type of titration will the ph be basic at the equivalence point?
Pavel [41]

Answer:

weak acid

Explanation:

3 0
3 years ago
Is nitrogen and cobalt and carbon a mixture or pure substance
Mashutka [201]
Nitrogen pure
carbon is mixture
3 0
3 years ago
State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
3 years ago
Given a Ksp for AgBr of 5.0 * 10–13, what happens when 50 ml of 0.002 M AgNO3 and 50 mL of 0.002 M NaBr are mixed?
IrinaK [193]

Answer:

A precipitate will be produced

Explanation:

The Ksp of AgBr is:

AgBr(s) → Ag⁺ + Br⁻

5.0x10⁻¹³ = [Ag⁺] Br⁻]

<em>Where [] are the concentrations in equilibrium of each ion.</em>

<em />

And if Q is:

Q = [Ag⁺] Br⁻]

<em>Where the concentrations are actual concentrations of each ion</em>

<em />

We can say:

IF Q >= Ksp, a precipitate will be produced

IF Q < Ksp, no precipitate will be produced.

the molar concentrations are:

[AgNO₃] = [Ag⁺] = 0.002M * (50mL / 100mL) = 0.001M

<em>Because 50mL is the volume of the AgNO₃ solution and 100mL the volume of the mixture of both solutions.</em>

[NaBr] = [Br⁻] = 0.002M * (50mL / 100mL) = 0.001M

Q = [0.001M] * [0.001M]

Q = 1x10⁻⁶

As Q > Ksp,

<h3>A precipitate will be produced</h3>
5 0
3 years ago
What is the pH of 0.0001 M NaOH
kow [346]
Well. NaOH is a base. That's the first thing you need to watch for.
So to find the pOH, you take -log(.0001)
that would be 4. So now you have the pOH and <u>you still need to find the pH
</u>To find pH from pOH, you take 14(the maximum pH,sorta)-pOH(in this case 4)
14-4=10 The pH of NaOH is 10
5 0
3 years ago
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