Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4
Hence P(Y=1|X=3)=0.125
The three items cost altogether is : 111.32 + 28.75 + 73.21 = 213.28
So, he must work 213.28 : 8.75 = 24.3748571429...
Since if he works 24 hours, he wouldn't have enough money to buy the 3 items, so he must work 24 + 1 = 25 hours.
Recheck : 25 x 8.75 = 218.75 ( > 213.28)
Answer:
44+50 =94 in²
Step-by-step explanation:
Trapezoid
A= 1/2h(b1+b2)
A= 1/2*4(7+15)
A=1/2*4(22)
A=44
Rectangle
A=l*w
A=5*10
A=50
44+50 =94 in²
