Answer:
12 sq mi
Step-by-step explanation:
base times height divided by 2
Let's divide the shaded region into two areas:
area 1: x = 0 ---> x = 2
ares 2: x = 2 ---> x = 4
In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.
Area 1:
![A\frac{}{1} = ∫g(x)dx = ∫xdx = \frac{1}{2} {x}^{2} | \frac{2}{0} = 2](https://tex.z-dn.net/?f=A%5Cfrac%7B%7D%7B1%7D%20%20%3D%20%E2%88%ABg%28x%29dx%20%3D%20%20%E2%88%ABxdx%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Bx%7D%5E%7B2%7D%20%20%7C%20%5Cfrac%7B2%7D%7B0%7D%20%20%3D%202)
Area 2:
![A\frac{}{2} = ∫(g(x) - f(x))dx](https://tex.z-dn.net/?f=A%5Cfrac%7B%7D%7B2%7D%20%20%3D%20%E2%88%AB%28g%28x%29%20-%20f%28x%29%29dx)
![= ∫(x - {(x - 2)}^{2} )dx](https://tex.z-dn.net/?f=%3D%20%E2%88%AB%28x%20-%20%20%7B%28x%20-%202%29%7D%5E%7B2%7D%20%29dx)
![= ∫( - {x}^{2} + 5x - 4)dx](https://tex.z-dn.net/?f=%20%3D%20%20%E2%88%AB%28%20-%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20-%204%29dx)
![= ( - \frac{1}{3}{x}^{3} + \frac{5}{2} {x}^{2} - 4x) | \frac{4}{2}](https://tex.z-dn.net/?f=%3D%20%28%20-%20%5Cfrac%7B1%7D%7B3%7D%7Bx%7D%5E%7B3%7D%20%2B%20%20%20%5Cfrac%7B5%7D%7B2%7D%20%7Bx%7D%5E%7B2%7D%20%20-%204x%29%20%20%20%7C%20%5Cfrac%7B4%7D%7B2%7D)
![= 2.67 - ( - 0.67) = 3.34](https://tex.z-dn.net/?f=%20%3D%202.67%20-%20%28%20-%200.67%29%20%3D%203.34)
Therefore, the area of the shaded portion of the graph is
A = A1 + A2 = 5.34
So the unit rate is basically how many ounces in 1 cup?
So since there are 64 ounces in 8 cups, you can just divide by 8, to find how many sets of 8 there are in 64.
64 = 8
64 / 8 = 8 / 8
8 = 1
So there are 8 ounces in 1 cup, which is your unit rate.
Definition: A histogram visualises the distribution of data over a continuous interval or certain time period. Each bar in a histogram represents the tabulated frequency at each interval.
According to the given histogram,
0-20 years occur 15 times,
21-40 years occur 40 times,
41-60 years occur 40 times,
61-80 years occur 15 times.
This shows that the data is symmetrical and the majority of the attendees were between the ages of 21 and 60 (40 times).
Answer: correct choice is B.