Ask question

Ask question

All categories

3 years ago

7

Is O a solution to each equation? Be sure to plug in "O" every time an x appears & then solve. If both numbers on either sid

e of the equal sign
are the same, then it is a solution.
a) 4(x + 2) = 10
b) 12 - 8x = 3 (2+4)
c) 5x =
d) 9 + 1 = 8
nect

1 answer:

suter [353]3 years ago

3 0

The anser is B I did the math

You might be interested in

Five hundred dollars more than 10% of am amount of money $m is $1280. Find m.

In-s [12.5K]

For this one, we need to make an equation to make it look easier
(0.10 × m) + 500 = 1280
We solve for m
Subtract 500 from both sides and we get
0.10 × m = 780
Now, divide both sides by 0.10
And m would be equal to 7800
Let's see if this is correct.
Five hundred dollars more than 10% of m
We found that 10% of m is 780, now we add 500 to make the statement true. It will give us a total of 1280, which is equal of what the question says.
I hope this helps.
YOU'RE WELCOME :D

*brainliest*

6 0

2 years ago

In a local basketball league championship total 198 games were played, where each team played exactly three games with all the o

kifflom [539]

Answer:

12

Step-by-step explanation:

When n teams play each other once, the total number of games is n(n-1)/2. Since each team played every other one 3 times, the relationship between number of teams (n) and number of games is ...

3(n(n-1)/2) = 198

n(n-1) = 132 = 12·11 . . . . . . multiply by 2/3 and factor

n = 12 . . . . . . n = -11 is also an extraneous solution to this quadratic equation

12 teams participated in this championship.

6 0

3 years ago

I need number 1 please and thank you

belka [17]

Answer:

It is the third one because of formula I² + 2I*II + II²

In your case I = 4x and II = 3

4 0

2 years ago

Hi I need question 5 solved using SOH CAH TOA!

Bond [772]

According to the trigonometric functions, we can see that angle x can be found through the one that involves the adjacent side and the hypotenuse, which in this case is the cos,

$cos(x)=\frac{27}{30}$

then, if we apply the inverse we can find the value of x,

$\begin{gathered} cos^{-1}(cos(x))=cos^{-1}(\frac{27}{30}) \\ x\cong25.8 \end{gathered}$

Answer:

$x\cong25.8$

5 0

1 year ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

4 0

2 years ago

Read 2 more answers