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Anika [276]
3 years ago
5

Use the completing the square method to find the roots of 2x^2+3x-15=13 include the steps, it would be greatly appreciated thank

s!!
Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

The roots are

x1= \frac{-3+\sqrt{233}}{4}

x2= \frac{-3-\sqrt{233}}{4}

Step-by-step explanation:

we have

2x^{2}+3x-15=13

so

Group terms that contain the same variable, and move the constant to the opposite side of the equation

2x^{2}+3x=13+15

2x^{2}+3x=28

Factor the leading coefficient  

2(x^{2}+(3/2)x)=28

Complete the square. Remember to balance the equation by adding the same constants to each side

2(x^{2}+(3/2)x+(9/16))=28+(9/8)

2(x^{2}+(3/2)x+(9/16))=233/8

(x^{2}+(3/2)x+(9/16))=233/16

Rewrite as perfect squares

(x+(3/4))^{2}=233/16

square root both sides

(x+\frac{3}{4})=(+/-)\sqrt{\frac{233}{16}}\\ \\(x+\frac{3}{4})=(+/-)\frac{\sqrt{233}}{4}\\ \\x= -\frac{3}{4}(+/-)\frac{\sqrt{233}}{4}

x1= -\frac{3}{4}(+)\frac{\sqrt{233}}{4}=\frac{-3+\sqrt{233}}{4}

x2= -\frac{3}{4}(-)\frac{\sqrt{233}}{4}=\frac{-3-\sqrt{233}}{4}

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