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Anika [276]
3 years ago
5

Use the completing the square method to find the roots of 2x^2+3x-15=13 include the steps, it would be greatly appreciated thank

s!!
Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

The roots are

x1= \frac{-3+\sqrt{233}}{4}

x2= \frac{-3-\sqrt{233}}{4}

Step-by-step explanation:

we have

2x^{2}+3x-15=13

so

Group terms that contain the same variable, and move the constant to the opposite side of the equation

2x^{2}+3x=13+15

2x^{2}+3x=28

Factor the leading coefficient  

2(x^{2}+(3/2)x)=28

Complete the square. Remember to balance the equation by adding the same constants to each side

2(x^{2}+(3/2)x+(9/16))=28+(9/8)

2(x^{2}+(3/2)x+(9/16))=233/8

(x^{2}+(3/2)x+(9/16))=233/16

Rewrite as perfect squares

(x+(3/4))^{2}=233/16

square root both sides

(x+\frac{3}{4})=(+/-)\sqrt{\frac{233}{16}}\\ \\(x+\frac{3}{4})=(+/-)\frac{\sqrt{233}}{4}\\ \\x= -\frac{3}{4}(+/-)\frac{\sqrt{233}}{4}

x1= -\frac{3}{4}(+)\frac{\sqrt{233}}{4}=\frac{-3+\sqrt{233}}{4}

x2= -\frac{3}{4}(-)\frac{\sqrt{233}}{4}=\frac{-3-\sqrt{233}}{4}

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Makovka662 [10]

Answer:

a : c = 6 : 5

Step-by-step explanation:

Expressing the ratios in fractional form, then

\frac{a}{c} = \frac{a}{b} × \frac{b}{d} × \frac{d}{c} = \frac{1}{2} × \frac{4}{5} × \frac{3}{1} = \frac{12}{10} = \frac{6}{5}

Thus a : c = 6 : 5

3 0
3 years ago
The sum of one and the product of a number and two is thirteen
Zigmanuir [339]

Answer:

2x + 1=13

Step-by-step explanation:

the product of a number and 2 (2x)

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6 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

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t= \frac{-80\pm \sqrt{25600}}{-32}  

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8 0
3 years ago
Ardem collected data from a class survey. He then randomly selected samples of five responses to generate four samples.
scoundrel [369]

Solution: The sample mean of sample 1 is:

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The sample mean of sample 2 is:

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The sample mean of sample 3 is:

\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6

The sample mean of sample 4 is:

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The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.

Therefore, using  his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.

Hence the option 3.6 and 4.4 is correct

6 0
3 years ago
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Pls help me plssss help asap
Anestetic [448]

Answer:

1) 15

2) 18

3) 72

8 0
3 years ago
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