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vfiekz [6]
2 years ago
10

Part E

Chemistry
1 answer:
Nata [24]2 years ago
4 0

Answer:

make the house elevated

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6 0
3 years ago
How many decigrams are in 4.6 decagrams?
11111nata11111 [884]

Answer:

\large \boxed{\text{460 dg}}

Explanation:

1. Convert decagrams to grams

\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}

2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

3 0
4 years ago
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How many moles of helium atoms are there in 0.02g of helium
MAVERICK [17]
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7 0
4 years ago
Help me on number 4 and that last one says blood pressure
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4 0
4 years ago
How many grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution?
Alexus [3.1K]

Answer: 724.71 grams

Explanation:

Volume of solution (v) = 5.1 liters

Concentration of solution (c) = 1.4M

Amount of CuF2 needed (n) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.4M x 5.1 Liters

n = 7.14 moles

Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.

The atomic masses of Copper = 63.5g;

and Fluorine = 19g

So, I CuF2 = 63.5g + (19g x 2)

= 63.5g + 38g

= 101.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

7.14 moles = m / 101.5 g/mol

m = 7.14 moles x 101.5 g/mol

m = 724.71g

Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution

7 0
4 years ago
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