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Harman [31]
3 years ago
15

I know the correct answer is either a or d. Can anyone explain which one it is and why? CH3C ≡ CCH2CH2Cl is named: a. 1-chloro-3

-pentyne b. 5-chloro-2-pentene c. 1-acetylenyl-3-chloropropane d. 5-chloro-2-pentyne
Chemistry
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

D.

Explanation:

CH₃C≡ CCH₂CH₂Cl

Since there are 5 carbons so the suffix used is "pent"

There is a triple bond so its alkyne

So the compound becomes 2-pentyne (2 because the triple bond is with the 2nd carbon)

Then,

The functional group of chlorine is attached with 5th carbon So the compound becomes

5-chloro,2-pentyne

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Write the net ionic equation for the reaction of aqueous copper(II) chloride with aqueous sodium phosphate. Remember to include
sergeinik [125]

Answer:

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

Explanation:

Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.

3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)

The complete ionic equation includes all the ions and insoluble species.

3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

7 0
3 years ago
How many moles of NaCl are needed to make 10.0L of a 5 M solution of<br> Salt water?*
vesna_86 [32]

Answer: 50 mol

Explanation:

Molarity=\frac{Moles -of -solute}{liters -of -solution}

M=\frac{mol}{L}

mol=M*L

mol=5*10\\mol=50mol

3 0
3 years ago
_____ is an example of a heterogeneous mixture.
Rus_ich [418]

B) Salad

heterogeneous mixtures have a non-uniform composition with components in at least two different phases

8 0
3 years ago
Pls help! DO NOT GIVE ME A LINK AS AN ANSWER!
melisa1 [442]

Answer:

(top to bottom)

0.50

0.63

0.83

1.0

1.3

2.5

Explanation:

8 0
3 years ago
If 309 grams of potassium combines with 228 g chlorine gas, how many grams of the single product will be formed? What are the LR
lisov135 [29]

The amount of KCl that would be formed will be 478.8 grams

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the mole ratio of K to Cl_2 is 2:1.

Mole of 309 g potassium = 309/39 = 7.92 moles

Mole of 228 g Cl2 = 228/71 = 3.21 moles

Thus, potassium is in excess while Cl2 is limiting.

Mole ratio of Cl2 and KCl = 1:2

Equivalent mole of KCl = 3.21 x 2 = 6.42 moles

Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

4 0
2 years ago
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