Answer:
Element atom molar mass Total % composition
Na 1 23 40 57.5 %
O 1 16 40 40%
H 1 1 40 2.5 %
The given compound is NaOH.
Na : number of atom= 1
Molar mass= 23 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass =
O : number of atom= 1
Molar mass= 16 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass =
H : number of atom= 1
Molar mass= 1 g/mol
Total mass of NaOH = 40 g/mol
% composition by mass =
Answer:
1.389 moles
Explanation:
We are given that
Given mass of ammonium=25.0 g
We have to find the number of moles in 25.0g of ammonium.
The chemical formula of ammonium
Molar mass of N=14, Molar mass of H=1
Molar mass of ammonium (NH4+)=14+4(4)=18 g/mol
We know that
Number of moles=Given mass/Molar mass
Using the formula
Number of moles of ammonium=moles
Number of moles of ammonium=1.389 moles
Hence, the number of moles in 25.0g of ammonium=1.389 moles