Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.
Hey there! This is gonna require the Pythagorean Theorem which is<span> a^2 + b^2 = c^2
</span>
a and b in this case are the legs while c is the hypotenuse! So, we can just plug in the numbers we know!
3^2 + 10^2 = c^2
9 + 100 = c^2
109 = c^2
And then take the square root of 109 to get the hypotenuse.
<span>10.4403065089 = c
</span>
Since we need to round to the nearest hundredth, though, it would be 10.44
I hope that helps! Feel free to let me know if you have any questions!
- mathwizzard3
Answer: The raw score for Daniel's exam grade is 101.69.
Step-by-step explanation:
For x be any random variable.
Formula for z-score :
, where
= population mean
= population standard deviation.
Let x be the raw score for Daniel's exam grade.
As per given , we have
,
and z= 1.67 , put these values in the above formula , we get

Hence, the raw score for Daniel's exam grade is 101.69.
Its B
-130 + 240= 110
110- 56 = 54
So.. 54 is your answer
4x-3 is the answer because you subtract like terms. 7x-3x=4x and -5-(-2)=-3