For which triangle is the length of the hypotenuse an INTEGER?

Mathematics

1 answer:

artcher [175]3 years ago

4 0

A right triangle :) to find the length of a missing side, you can use the pythagorean theorem (a^2 + b^2 = c^2)

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Will give brainliest answer!

kifflom [539]

5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y and substitute this formula for x in the first one:

5(1.5-y) + 60y = 35

distribute:

7.5 - 5y + 60y = 35

combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

he walked for 1 hour

8 0

3 years ago

when you reverse the digits in a certain two-diget number you increase it value by 27. What is the number if the sum of its digi

Fynjy0 [20]

The number is = 10x+y
if reverse the digits, the number is: 10y+x
The sum fo its digits is = x+y=5
I suggest this system of equations:
(10y+x)-(10x+y)=27 ⇒9y-9x=27
x+y=5
We can solve this system of equations by equaliztion method
x=5-y

9y-9(5-y)=27
9y-45+9y=27
18y=27+45
18y=72
y=72/18
y=4

x=5-y
x=5-4=1

The number is: 10x+y=10(1)+4=14

Answer: the number is 14

3 0

3 years ago

Read 2 more answers

Help with Pre Calculus

marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. $x(2x^2-x-15)$ . So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\$ . So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}$