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qwelly [4]
3 years ago
15

What is the slope of the line which passes through (4, 5) and (0, 1)?

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0
The answer would be B. 
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The two shortest sides of a right triangle are 10 in. And 24 in. long. What is the length of the shortest side of a similar righ
ivanzaharov [21]
If the two shortest sides of the triangle are 10in and 24in, then using Pythagoras' theorem, the longest side =
\sqrt{10^2 + 24^2} 
= \sqrt{676}
= 26

Now we know the two longest sides of the first triangle (24in and 26in) we can compare them with the two longest sides of the second triangle.
If x = the scale factor the first triangle is enlarged by then
26x = 39 and 24x = 36 
⇒ x = 1.5

Finally, we need to multiply the smallest side of the first triangle by the scale factor to find the shortest side of the second triangle.
10(1.5) = 15
So the length of the shortest side of the other triangle is 15in.

You could, instead, calculate the length of the shortest side of the second triangle by using Pythagoras' theorem and ignoring the first triangle completely.
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What event would be complementary to the event that the product is an even number?
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The equation (x + 6)^2 + (y + 4)^2 = 36 models the position and range of the source of a radio signal. Describe the position of
ElenaW [278]
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( x - p )² + ( y - q )² = r², where p and q are coordinates of the center.
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Use compatible numbers to find two estomatoes 27÷735
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2 years ago
Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d
Olegator [25]

Answer:

The speed of the cars is 32 \frac{km}{h}

Step-by-step explanation:

First we must first have the clear concept that speed=\frac{distance}{time} or s=\frac{d}{t}

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: s_{1}=s+1 , t_{1}=2 and d_{1}= d_{2}

Car 1: s_{2}=s-10 , t_{2}=3 and d_{1}= d_{2}

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

d_{1}=s_{1}*t_{1}

d_{1}=(s+1)*2

d_{1}=2s+2

<em>Car 2</em>

d_{2}=s_{2}*t_{2}

d_{2}=(s-10)*3

d_{2}=3s.30

d_{1}=d_{2}

2s+2=3s-30

2+30=3s-2s

32=s

The speed of the cars is 32 km/hr

7 0
3 years ago
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