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3 years ago

Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

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bagirrra123 [75]

The series as represented in the task content is divergent and hence; diverges.

<h3>What convergence and divergence in series?</h3>

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1 year ago

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Nitella [24]

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<u><em>Solution:</em></u>

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

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<em><u>Caroline gets twice as much as Sarah</u></em>

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

<em><u>Sarah gets three times as much as Gavyn</u></em>

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

<em><u>Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"</u></em>

From eqn 2,

$g = \frac{s}{3}$ --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

$2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294$

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3 years ago

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algol [13]

Answer:

hello : x = 2

Step-by-step explanation:

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x^3-8=0

x^3=8

x^3= 2^3

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Sedaia [141]

<h3>Answer:</h3>

A) p = 5, one solution
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<h3>Step-by-step explanation:</h3>

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