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3 years ago

Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

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2 years ago

What is the standard form of the points (-3,4) (2,-6)

Bas_tet [7]

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To solve this problem, the following steps would be taken:

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Substitute

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Step 4: Rewrite the equation in standard form $(Ax + By = C)$

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Add $2x$ to both sides

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The standard form equation of the points (-3,4) and (2,-6) is $2x + y = -2$

Learn more about standard form of two points of a linear equation here:

brainly.com/question/18446164

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hodyreva [135]

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3 years ago