A coin is tossed 100 times. Consider the following statements:

Mathematics

1 answer:

shusha [124]3 years ago

4 0

Answer:

1. and III.

Step-by-step explanation:

Option 1 and 3 are correct.

The probability of landing on heads would be 1/2, so 50 times in 100. This is the expected outcome, so option 1 is correct.

However, that is just the most probable outcome, probability is almost never 100% accurate. Therefore, the number of heads will most likely be 50, give or take 5 or so. Therefore, option 3 is also correct.

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the rhombus.

anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

$JL = 48$

$KM = 20$

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

$P = 2\sqrt{(JL)^2 + (KM)^2}$

Substitute values for JL and KM

$P = 2\sqrt{48^2 + 20^2}$

$P = 2\sqrt{2304 +400}$

$P = 2\sqrt{2704}$

$P = 2 * 52$

$P = 104$

Hence, the perimeter is 104 units

5 0

3 years ago

If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac

mezya [45]

There are $\binom{52}4$ ways of drawing a 4-card hand, where

$\dbinom nk = \dfrac{n!}{k!(n-k)!}$

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are $\binom{13}4$ ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are $\binom41$ ways of picking a card of any given value. We draw 4 cards from the deck, so there are $\binom41^4$ possible hands in which each card has a different value.