Answer:
Simplify the equation as closely as possible to the form of y = mx + b. Check to see if your equation has exponents. If it has exponents, it is nonlinear (exponential). If your equation has no exponents, it is linear.
Answer:
Mine
Step-by-step explanation:
Mine because people change up and everybody is not your friend everyone always have alot of animosity towards me but I didn't care anyways because my motha raised me to not have friends thats why i'm antisocial
Please consider the attached file.
We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.
We will use Pythagoras theorem to solve for KJ as:




Now we will take positive square root on both sides:



Therefore, the length of line segment KJ is
and option D is the correct choice.
Answer:
your answer would be c because for the team's average yardage per quarter it can't be negative!
Step-by-step explanation:
C. -56÷(-4)= 14
Mark me brainlest!!
I've done this before.
12h-9h=3h move everything else to other side
3h=20-40+6
3h=-14
divide by 3
h=-14/3