For
(x-h)^2=4p(y-k)
vertex is (h,k)
distance from vertex to directix=p=distance from vertex to focus
|4p|=focal width
remember, focus is on the side of the parabola where it opens and directix is at the back
when p is negative, it opens down
when p is positive, it opens up
look at equation
-1/40(x-0)^2=(y-0)
times -40 to both sides
(x-0)^2=-40(y-0)
(x-0)^2=4(-10)(y-0)
vertex=(0,0)
p=-10,it's negative so it opens down
focus is 10 units below vertex (y direction)
focus=(0,-10)
diretix is 10 above
directix is y=10
focal width=|4p|=|4(-10)|=|-40|=40
vertex=(0,0)
focus=(0,-10)
directix is y=10
focal width=40 units
Answer:
y+48
Step-by-step explanation:
If pq=7 and qr=28 then,
p=7/q and r=28/q
pr=7/q×28/q
pr=196/q^2
Hope it helps you
