6 (3) - 4 + 32
hope this helped
Number: n
square of number: n^2
sum of n and n^2 is n+n^2=20
Rewriting this equation, we get n^2+n-20=0 = (n+5)(n-4) = 0
Then n+5=0 and n-4=0, so n = -5 and n = 4.
You must check both results. It could happen that both are correct, or that only one is correct.
Step-by-step explanation:
x = amount of shares for $6.25
y = account of shares for $6.50
x + y = 500
x×6.25 + y×6.5 = 3218.75
x = 500 - y
(500 - y)×6.25 + y×6.5 = 3218.75
3125 - y×6.25 + y×6.5 = 3218.75
0.25×y = 93.75
y = 375
x = 500 - 375 = 125
so, he bought
375 shares of $6.50
125 shares of $6.25
Answer:
A. 0.5
B. 0.32
C. 0.75
Step-by-step explanation:
There are
- 28 students in the Spanish class,
- 26 in the French class,
- 16 in the German class,
- 12 students that are in both Spanish and French,
- 4 that are in both Spanish and German,
- 6 that are in both French and German,
- 2 students taking all 3 classes.
So,
- 2 students taking all 3 classes,
- 6 - 2 = 4 students are in French and German, bu are not in Spanish,
- 4 - 2 = 2 students are in Spanish and German, but are not in French,
- 12 - 2 = 10 students are in Spanish and French but are not in German,
- 16 - 2 - 4 - 2 = 8 students are only in German,
- 26 - 2 - 4 - 10 = 10 students are only in French,
- 28 - 2 - 2 - 10 = 14 students are only in Spanish.
In total, there are
2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.
The classes are open to any of the 100 students in the school, so
100 - 50 = 50 students are not in any of the languages classes.
A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

So, the probability that at least 1 is taking a language class is
