The value of zu(1,3) using the data elements represented on the table of values is q + p
The given parameters are:
z = f(x, y)
x = x(u, v)
y = y(u, v)
Where
x(1, 3) = 2 and y(1, 3) = 2
To calculate zu(1,3), we make use of:
The values x(1, 3) = 2 and y(1, 3) = 2 mean that:
(x,y) = (2,2).
So, we have:
From the table of values, we have:
So, the equation becomes
Evaluate the product
Hence, the value of zu(1,3) is q + p
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Answer: m1 = 0.5
M2= 0.375
M3 = 2.25
M4 = 3.0
M5 = 13.5
M6 = 0.285
M7 = 7.0
Step-by-step explanation:
(20,40)-(15,30)=(5,10), m1=5/10=0.5
(18,48)-(12,32)=(6,16), m2=3/8=0.375
(72,32)-(27,12)=(45,20), m3=9/4=2.25
(60,20)-(45,15)=(15,5), m4=3.0
(243,18)-(27,2)=(216,16), m5=27/2=13.5
(24,84)-(18,63)=(6,21), m6=2/7=0.285...
(84,12)-(63,9)=(21,3), m7=7.0
Answer:
$550
5.5 % = 0.055
10,000 x 0.055=550
hi!
so the original equation is (x^2 -121) / x+ 11.
Those two equations look similar...
well, we know that the top equation looks like a^2 - b^2, and that equation iis equivalent to this equation: (a+b)(a-b).
So if we factor that out, we get:
( (x + 11) * (x-11) )/ (x + 11)
we can cancel the x+11 on the top and the x+11 on the bottom out.
that leaves us with x-11.
Hope this helped!
40 Apple juice and 20 Orange juice
From the diagram, you know that 4 OJ makes one drink, so to make 5 drinks, you need 5 times that, or 20 OJ. You can also see that you need twice as much AJ as OJ, so that means you need 40 AJ.
*OJ = Orange juice and AJ = Apple juice
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
We know that,
Subtract both sides by 25.
We need to find the number of people who have a school certificate only, i.e. .
Therefore, 9 people have a school certificate only.