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3 years ago

Rearranging Equations: Solve the equation for y: 8x + y = 14 Solve the equation for x: -9x + 3y = 18

Mathematics

1 answer:

podryga [215]3 years ago

7 0

Answer:

y=14-8x

x= -2 + 3y/9x

Step-by-step explanation:

8x+y=14

isolate y so you get:

y=14-8x

-9x+3y=18

isolate x so you get:

-9x=18-3y

divide on both sides to get x by itself

-9x/-9x 18-3y/-9x

x= -2 + 3y/9x

Hope this helps :)

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. If ON = 4x – 6, LM = 3x + 5, NM = x – 4, and OL = 4y – 3, find the values of x and y for which LMNO must be a parallelogram.

Verizon [17]

In a parallelogram, opposite sides are congruent.

This means that
LM = ON
NM = OL

Using the equations, find x and y:
4x - 6 = 3x + 5
4x = 3x + 11
1x = 11
x = 11

x - 4 = 4y - 3
x - 1 = 4y
-1 = 3y
-1/3 = y

The values are:
x = 11
y = -1/3

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3 years ago

A scatter plot was constructed and a line of best fit was drawn, 25x 80. What is the equation of this best line of fit?

Tcecarenko [31]

Answer:

y = 5x + 25

Explaination:

To get the equation of a line, first get the slope of the line.

Slope = (change in y)/(change in x)

= (60-30)/(7-1)

= 30/6

= 5

Now use one point in the line (4,45) and a general point (x,y).

Slope = (change in y)/(change in x)

5 = (y - 45)/(x - 4)

5(x - 4) = (y - 45)

5x - 20 = y - 45

y = 5x -20 + 45

7 0

3 years ago

Write an expression for "the difference of 10 and x.

navik [9.2K]

10-x=d
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2 years ago

Find the area of the shaded part in the given diagram

enyata [817]

Answer:

30cm^2

Step-by-step explanation:

area of large rectangle = length x width

= 5 X 9 = 45 cm^2

area of small rectangle = length x width

= 3 X 5 = 15 cm ^2

45 - 15 = 30cm^2

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2 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago