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son4ous [18]
3 years ago
14

What is the answer to this question?

Mathematics
1 answer:
lions [1.4K]3 years ago
4 0
*Hint: The formula to solve this is SA = 2bs + b^2

Now that you know the formula, plug in and solve.

SA = 2(5)(8) + (5)^2
SA = 80 + 25
SA = 105

Now that you see that the question is asking for the answer in yards, you convert feet into yards.

3 feet = 1 yard.

105 is divided by 3 and you get 35.

The answer is 35 square yards.
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if I want a PlayStation for $300.00 and I get paid $10.50 a week how long would it take me to buy the PlayStation
konstantin123 [22]

Answer:

29 weeks or 4 months (not exactly)

Step-by-step explanation:

300/10.5 is 28.57

which 29 weeks, you earn 4 dollars and 50 cents left over

8 0
2 years ago
△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle
adelina 88 [10]

Answer:

Not a right triangle

Obtuse isosceles triangle.

Sides: J = 3.606   K = 6   L = 3.606

4 0
3 years ago
Read 2 more answers
Y=4x+2, what is y-intercept
EleoNora [17]
The y-intercept is (0,2)… Hope this helps..
3 0
2 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
Use the data set shown below to complete the sentence 3,3,4,5,5,9 the mean the median
lorasvet [3.4K]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ Mean = 4.8  Median = 4.5

The mean is the average. To find the mean add up all the numbers and divide by the number of numbers:

3 + 3 + 4 + 5 + 5 + 9 = 29

29 ÷ 6 = 4.8

To find the mean, keep crossing out numbers until you are left with one number (for an odd amount of numbers). When you have an even amount of numbers, keep crossing out until you are left with 2 numbers. Add those 2 numbers and then divide:

4 + 5 = 9

9 ÷ 2 = 4.5

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0
3 years ago
Read 2 more answers
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