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lorasvet [3.4K]
1 year ago
8

Nicole is deciding between two different movie streaming sites to subscribe to. Plan A costs $24 per month plus $1.50 per movie

watched. Plan B costs $12 per month plus $3 per movie watched. Let AA represent the monthly cost of Plan A if Nicole watches xx per month, and let BB represent the monthly cost of Plan B if Nicole watches xx movies per month. Graph each function and determine the interval of movies watched, x,x, for which Plan A is cheaper than Plan B.
Mathematics
1 answer:
xz_007 [3.2K]1 year ago
5 0

Answer:

Plan B

Step-by-step explanation:

If you multiply 21 by $2.50 you get $52.5 then add $5 you get 57.5 and that's you outcome for Plan A

but if you multiply 21 by $1.50 you get $31.5 then add $24 you get $55.5 so the best and cheapest plan would be Plan B

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GIVING 20 POINTS What is the product?
natta225 [31]

Answer:

1

Step-by-step explanation:

4^3 × 4^-3

Apply the law of exponents.

4^(3+-3)

4^(0)

Any base with the exponent of 0 is equal to 1.

= 1

5 0
3 years ago
Read 2 more answers
If each value of the data of the poplation function is doubled which of the following is not correct?
Anna35 [415]

Answer:

The variance is doubled; C

Step-by-step explanation:

Here, we want to select what will be wrong if every number in the dataset is doubled

A. This is correct

The mean is the average of the numbers which is calculated by dividing the sum of the numbers by the count of the numbers

By doubling the numbers, we have simply doubled the sum while the count is same

So what we have as the result of the division will be 2 times what we had initially making the mean doubled

B. The mode is doubled

Yes, this is correct

The mode is the highest in frequency

Doubling all numbers will not double their frequencies but their values. So the number that was the mode in the previous case will be the same but now doubled

D. The median is doubled

This is correct

The median deals with the middle number.

Since all numbers are doubled in the present case, the median to is also doubled along side as the numbers are now twice what they were evenly

C. This is wrong

The variance has to do with the spread of data

We are actually subtracting values

Since we are doubling across board, the difference between the numbers is the same as this, the variance cannot change

We can look at this from the angle that all others are measures of central tendency looking at having a central figure while the variance is a measure of spread.

3 0
2 years ago
Miguel collected aluminum cans for recycling. He collected a total of 150 cans. If 58% of the cans he collected were soda cans h
Romashka-Z-Leto [24]

Given:

• Total number of cans collected = 150

,

• Percent of cans that were soda = 58%

Let's find the number of other cans he collected.

To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.

Percent of other cans = 100% - 58% = 42%

The percent of other cans collected was 42%.

Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.

We have:

42\text{ \% }\ast150\Longrightarrow0.42\times150=63

Therefore, the number of other cans collected is 63 cans.

ANSWER:

63 cans

4 0
11 months ago
You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

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\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

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\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
2 years ago
Answer the question about the promissory note given.
myrzilka [38]
That he is keeping track who he owes money to and when he has to do it
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