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Yakvenalex [24]
3 years ago
11

Which of the following rules represents the function shown in the table?

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
6 0
<h2>Answer:</h2>

The rule which represent the function as shown in the table is:

                 f(n)=3n

<h2>Step-by-step explanation:</h2>

We are given a table as follows:

  x       2          -1         0

  y       6          -3         0

Now we are asked to find the function which represent these table of values.

a)

    f(n)=n+3

Here x is represented by n and y by f(n)

when n=2 we must have f(n)=6

Hence, we put n=2 in the given expression and check,

f(2)=2+3=5\neq 6

Hence, this is not a correct function.

b)

f(n)=\dfrac{1}{3}n

Again we check for n=2

We have:

f(2)=\dfrac{1}{3}\times 2=\dfrac{2}{3}\neq 6

Hence, it is not a correct expression.

So we are left with option: c)

c)

f(n)=3n

By putting the value of n=2,-1 and 0

we see that the expression matches the table of values.

( since,

when n=2 we have:

f(2)=3\times 2=6

when n= -1 we have:

f(-1)=3\times -1=-3

and when n=0 we have:

f(0)=3\times 0=0 )

Hence, this is a correct expression.

Lesechka [4]3 years ago
4 0

This is F(n) = 3n

The X is an interger which is holding a value

The relationship between Y and X is 3n as we multiply X by 3 to get the value of Y and is proven yet so.

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The dog eats 6 cupcakes in 22 days.

<em>(don't know why a dog would be eating cupcakes in the first place, but sometimes math questions don't make the most sense)</em>

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2 years ago
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Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

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(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

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4 0
3 years ago
After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),
Rasek [7]

Answer:

<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
  • 180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]

→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

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AVprozaik [17]

Answer:

You would just plug in the x’s for the equations above and that will equal your x

Step-by-step explanation:

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the equation is x+5

so y equals 1+5=6

y=6

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What is m in equation 2m=12
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M is equal to 6 because 6 times 2 would equal 12
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