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KATRIN_1 [288]
1 year ago
9

Fing the LCM of 54 and 81

Mathematics
2 answers:
mina [271]1 year ago
5 0
The lcm of 54 and 81 is the smallest positive integer that divides the numbers 54 and 81 without a remainder. Spelled out, it is the least common multiple of 54 and 81
Lilit [14]1 year ago
5 0

Step-by-step explanation:

Factor of 54

= 2 \times 3 \times 3 \times 3

Factor of 81

= 3 \times 3 \times 3 \times 3

Now ...

Common factor = 3 × 3 × 3

= 27

LCM = common factor × remaining factors..

= 27 × 2 × 3

= 162

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Tomic and Brooke make a game of shooting free throws. Each basket is worth 2 1/2 points. Each miss is worth −3/4 points. Out of
Sergeu [11.5K]
Answer: 29.5 points

Why: the missed 14 shots so 14 x 3/4 is 10.5
They made 16 shots so 16 x 2.5 is 40
40-10.5=29.5
8 0
3 years ago
What else would need to be congruent to show that ABC=DEF by SAS?
KonstantinChe [14]

Answer:

A

Step-by-step explanation:

SAS = side-angle-side

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We know that sides AB, ED, AC, and DF are all congruent as they all have a single mark through them. From this, you can conclude that the triangles already share two sides. All we need now is the angles in between to be congruent. This means that angle A and angle D need to be congruent.

I hope this helps!

7 0
3 years ago
Simplify the expression -4-6(7-3)
alexandr1967 [171]

-18

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7 0
3 years ago
Read 2 more answers
These two trapezoids are similar What is the correct way to complete the similarity statement?
pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

3 0
3 years ago
A bakery has 2,160 loaves of whole-wheat bread in July. In all, the bakery SOLD 9000 loaves THIS MONTH. What percent of the loav
Bumek [7]
24% because you would make a ratio like x/100= 2,160/9000. So basically the x is the percentage you need, 100 is just an easy factorable percent, and 2,160 is the wheat bread and 9000 is all the bread. Basically what you do with this ratio is you cross multiply. This means you multiply 2,160 by 100 and divide by 9000 and that’s your percent
3 0
3 years ago
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