Answer:
Play 3
Step-by-step explanation:
Given:
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
1 7/10 is equivalent to the improper fraction 17/10
X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve
y = -2/3x - 4
simply plug into y = mx+b where m is slope and b is y intercept
