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adelina 88 [10]
3 years ago
14

I need help on this problem!

Mathematics
1 answer:
labwork [276]3 years ago
8 0
About 34 games (34.2)
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What is 2.1 times 3.2 find the missing partial products HELP.​
vredina [299]

Given:

The area model for 2.1\times 3.2.

To find:

The value of 2.1\times 3.2 and the missing values in the area model.

Solution:

2.1 can be written as 2 and 0.1 on the left side of the area model.

3.2 can be written as 3 and 0.2 on the top of area model.

Area of the four parts of the area model are:

2\times 3=6

2\times 0.2=0.4

0.1\times 3=0.3

0.1\times 0.2=0.02

The complete area model is shown below.

After adding all areas of the area model, we get

6+0.4+0.3+0.02=6.72

Therefore, the value of 2.1\times 3.2 is 6.72 and the missing values of the area model are 0.3 and 0.02 respectively.

8 0
3 years ago
Long division of 452.7 ÷ 15<br><br>help me!!​
Tpy6a [65]

Answer:

30.18

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Lucy collects data from a random sample of seventh-graders. Out of 40 respondents, 7 attend after-school programs. Of the 200 se
Shalnov [3]

Answer:

35

Step-by-step explanation:

For every 40 students, you add 7

Ratio:

Students : Students in afterschool programs

40:7

80:14

120:21

160:28

200:35

8 0
3 years ago
Can someone please help me out?
jek_recluse [69]

Answer:

Ligh blue

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An ice cream store has the pricing shown below. You want to determine the best value. The height of the cone is 4.5 in and the d
nignag [31]

Solution:

Step 1:

We will calculate the volume of ice cream in the single scoop

The volume of the ice cream will be

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3 \\ r=\frac{2in}{2}=1in(cone) \\ h=4.5in \\ r=\frac{3in}{2}=1.5in(radius\text{ of the hemisphere\rparen} \end{gathered}

By substituting the values, we will have

\begin{gathered} V=\frac{1}{3}\pi r^{2}h+\frac{2}{3}\pi r^{3} \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+\frac{2}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{14} \\ V=\frac{165}{14} \\ V=11.79in^3 \end{gathered}

Step 2:

We will use the formula below to calculate the volume of the two scoops of ic cream

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{4}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5in+\frac{4}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{7} \\ V=\frac{132}{7} \\ V=18.86in^3 \end{gathered}

Step 3:

We will use the formula below to calculate the volume of the three scoops of ic cream

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{6}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+2\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{297}{14} \\ V=\frac{363}{14} \\ V=25.93in^3 \end{gathered}

For the first ice cream with one scoop

\begin{gathered} 1in^3=\frac{3.50}{11.79} \\ 1in^3=\text{ \$}0.30 \end{gathered}

For the second ice cream with two scoops

\begin{gathered} 1in^3=\frac{4.50}{18.86} \\ 1in^3=\text{ \$}0.24 \end{gathered}

For the third ice cream with three scoops

\begin{gathered} 1in^3=\frac{5.50}{25.93} \\ 1in^3=\text{ \$}0.21 \end{gathered}

Hence,

The final answer is

The triple sold at $5.50 has the best value because it has the lowest price of $0.21 per cubic inch of the ice cream

3 0
1 year ago
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