If you would like to know how many hours did Eric practice the piano this week, you can calculate this using the following steps:

the piano: 3/4 of 8 hours = 3/4 * 8 hours = 6 hours

The correct result would be 6 hours.

7 0

2 years ago

What are the coordinates of the point on the directed line segment from (4, -3)(4,−3) to (9, -8)(9,−8) that partitions the segme

jekas [21]

Answer:

(7, -6)

Step-by-step explanation:

You want to find point X on the segment from A to B such that ...

(X -A)/(B -X) = 3/2

2(X -A) = 3(B -X) . . . . . . cross multiply

2X -2A = 3B -3X . . . . . eliminate parentheses

5X = 2A +3B . . . . . . . . add 3X +2A

X = (2A +3B)/5 . . . . . . . divide by 5

Filling in the given points for A and B, we have ...

X = (2(4, -3) +3(9, -8))/5 = (8+27, -6-24)/5 = (35, -30)/5

X = (7, -6)

The point that divides the segment in the proportions 3:2 is (7, -6).

8 0

3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

Msh

Rudiy27

a Anna drives her sisters at an a average of 60 mph and devive home

3 0

3 years ago